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lodash

error '_' is not defined no-undef

I use eslint to check my code ,and a error happen -- "error '_' is not defined no-undef". I write the code like this: new webpack.ProvidePlugin({ $: "jquery",//jquery jQuery: "jquery", "window.jQuery": "jquery", _:"lodash"//lodash }) and get .eslintrc.js, part of it like this: "env": { "browser": true, "commonjs": true, "es6": true, "jquery":true, }, before I add the jquery into ,it happen an error -- "error '_' is not defined no-undef". However, when I add lodash into ,just like that "'lodash':true".It doesn't work. Can you help me?

2022-01-18 13:25:07    分类:问答    lodash   eslint

Inheritance with Lo-Dash

I am trying to emulate inheritance in javascript using a the Lo-Dash javascript library. I am simply using _.extend to do so: function Parent() { var self = this; self.hello = function () { console.log('Hello from parent'); }; } function Child() { var self = this; _.extend(self, Parent); } Child.hello(); // Doesn't exist I thought this would work since all javascript functions are objects but obviously I am wrong. Why doesn't this work and how would I properly emulate inheritance using Lo-Dash?

2022-01-18 13:22:18    分类:问答    javascript   inheritance   lodash

How to configure babel correctly to use lodash-es?

I need to use lodash-es in my project, but I can't configure my babel correctly, it always reports errors like SyntaxError: Unexpected identifier hello.js import upperCase from 'lodash-es/upperCase' console.log(upperCase('lodash-es')); package.json { "scripts": { "demo": "babel-node hello" }, "devDependencies": { "@babel/cli": "^7.0.0", "@babel/core": "^7.0.0", "@babel/node": "^7.0.0", "@babel/preset-env": "^7.0.0" }, "dependencies": { "lodash-es": "4.17.11" } } .babelrc { "presets": [ "@babel/preset-env" ] } When run babel-node hello, it reports error like: > /javascript-babel-node-use-lodash

2022-01-17 11:38:31    分类:问答    javascript   babeljs   babel-node   lodash

Javascript Sum array of object values

I would think this is a surprisingly common and simple question but I cant seem to find what Im looking for If I had var array = [{"a":4,"b":5, "d":6}, {"a":4, "c":5}, {"c":4}] how do I sum the objects to get {"a":8,"b":5,"c":9, "d":6} using underscore, lodash, or something fairly quick and simple one liner?

2022-01-17 06:46:22    分类:问答    javascript   node.js   underscore.js   lodash

Create an array of objects with specific key, then remove that key from object

I have used lodash to create an array of objects from a specific key, then remove this given key from its object. I have this var cars = [{ "itemID": "-KUsw42xU-S1qA-y3TiI", // use this as key "name": "Car One", "qtd": "1" }, { "itemID": "-KUsw42xU-r1qA-s3TbI", "name": "Car Two", "qtd": "2" } ] Trying to get this: var cars = { "-KUsw42xU-S1qA-y3TiI": { "name": "Car One", "qtd": "1" }, "-KUsw42xU-r1qA-s3TbI": { "name": "Car Two", "qtd": "1" } } I have tried this approach, but I have no success. _.chain(a) .keyBy('itemID') .omit(['itemID']) .value();

2022-01-16 21:33:16    分类:问答    lodash

Restangular - _.contains() 不是函数(Restangular - _.contains() is not a function)

问题 如果您最近通过 bower 更新了 restangular,它将安装最新的 lodash - 新的 4.0。 然而,这是一个问题,因为 restangular/angular 现在会引发错误 - “_.contains() 不是函数。” 你怎么解决? 回答1 解决方案非常简单——你需要告诉 restangular 使用比最新的 lodash 更低的版本——3.10.0 通过 bower.json "lodash": "~3.10.0" https://github.com/mgonto/restangular/issues/1298 回答2 你不能把它放在 app.js 中吗 // If Restangular ever updates to lodash 4.0 remove this. _.contains = _.includes 回答3 如果您没有明确指定lodash的条目并且它作为restangular的依赖项安装,您可以卸载它们并重新安装lodash (3.10.1)以解决问题。 bower uninstall restangular bower uninstall lodash bower install --save lodash#3.10.1 bower install --save restangular 这样您就不需要进入bower.json文件。 来源

2022-01-16 07:22:47    分类:技术分享    javascript   angularjs   lodash   restangular

Restangular - _.contains() is not a function

If you have recently updated restangular through bower it will have installed the latest lodash - the new 4.0. However this is a problem as restangular/angular now throws the error - "_.contains() is not a function." How do you solve?

2022-01-16 03:55:44    分类:问答    javascript   angularjs   lodash   restangular

在构建'找不到名称'排除''时出现lodash错误(following lodash error on build 'Cannot find name 'Exclude'')

问题 我收到以下 lodash 错误 node_modules/@types/lodash/common/object.d.ts(1689,12) 中的错误:错误 TS2304:找不到名称“排除”。 node_modules/@types/lodash/common/object.d.ts(1766,12):错误 TS2304:找不到名称“排除”。 node_modules/@types/lodash/common/object.d.ts(1842,34):错误 TS2304:找不到名称“排除”。 回答1 解决方案 1 我也遇到了同样的问题,我尝试降级 typescript 版本和 lodash 版本,但没有任何效果,最后我尝试安装 @types/lodash,它成功了。 试试这个: npm i @types/lodash 希望能帮助到你。 如果上述解决方案不起作用,请尝试以下操作: 解决方案 2 实际问题是,Exclude 已添加到 2.8 版的打字稿中。 您可能有一个需要最低 typescript 2.8 的 @types/lodash 版本,如果您的 lodash 和 typescript 版本不匹配,就会发生这种情况。 因此,使用以下代码安装与 lodash 兼容的最后一个 typescript 2.3 版本: npm i -D @types/lodash@ts2.3

2022-01-16 00:55:03    分类:技术分享    angular   typescript   lodash

为什么 lodash 将我的数组转换为对象?(Why lodash converts my array into object?)

问题 我是 lodash 的新手,并创建了一个函数,该函数从值为 null 或空白的对象中删除键。 但是当我传递包含某些部分作为数组的对象时,它会删除数组并将其转换为对象。 以下是我尝试过的代码: _.mixin({ 'removeFalsies': this.removeFalsies }); _.mixin({ removeEmptyObjects: this.removeEmptyObjects }); removeFalsies (obj) { return _.transform(obj, function (o, v, k) { if (v && typeof v === 'object') { if (v !== '') { o[k] = _.removeFalsies(v); } } else if (v === false) { o[k] = v; } else if (v) { o[k] = v; } }); } removeEmptyObjects (obj) { return _(obj) .pickBy(_.isObject) .mapValues(_.removeEmptyObjects) .omitBy(_.isEmpty) .assign(_.omitBy(obj, _.isObject)) .value(); } 下面是我提供的 JSON

2022-01-15 19:22:39    分类:技术分享    javascript   lodash

使用 lodash,为什么流程中的 map 方法不起作用?(Using lodash, why is the map method within flow not working?)

问题 我有一个用户对象试图在其上使用 lodash map()方法让它只返回 userIds,同时过滤掉任何具有currentUserId的用户。 我想避免使用chain() ,因为它会拉入整个库,所以flow()方法似乎是完美的,但它没有映射到 Id 数组。 import { map, filter, flow, } from 'lodash'; const users = { 123: { uid: 123 }, 456: { uid: 456 } }; const currentUserId = 123; const userIds = _.flow( _.map(user => user.uid), _.filter(userId => userId !== currentUserId), )(users); 不幸的是,这将返回与传递给它的对象相同的对象。 如何获取包含所有非当前用户的用户 ID 的数组? 回答1 答案适用于标准版的 lodash。 请参阅@Vlaz 的答案以了解 lodash 的函数式编程版本。 当您编写_.map(user => user.uid)时,它实际上正在调用该函数。 您真正想做的是创建类似于_.map的函数,但已经设置了其中一个参数。 幸运的是,Lodash 有一个内置的来处理这种情况 - _.partialRight const

2022-01-15 17:39:51    分类:技术分享    javascript   lodash